Question:

A vector \( \mathbf{P} \) has components along X and Y axis having magnitude 2 units and 4 units respectively. A vector along negative X-axis, \( \mathbf{Q} \) has magnitude 6 units. Then vector \( (\mathbf{P} - \mathbf{Q}) \) is:

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When subtracting vectors, subtract their corresponding components along each axis.
Updated On: Feb 9, 2026
  • \( 4 (2 \hat{i} + \hat{j}) \)
  • \( -4 (2 \hat{i} - \hat{j}) \)
  • \( 4 (2 \hat{i} - \hat{j}) \)
  • \( -4 (2 \hat{i} + \hat{j}) \)
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The Correct Option is C

Solution and Explanation

Step 1: Vector Components.
The vector \( \mathbf{P} \) has components \( 2 \hat{i} + 4 \hat{j} \). The vector \( \mathbf{Q} \) is along the negative X-axis, so its components are \( -6 \hat{i} \). To find \( \mathbf{P} - \mathbf{Q} \), subtract the components: \[ \mathbf{P} - \mathbf{Q} = (2 \hat{i} + 4 \hat{j}) - (-6 \hat{i}) = 2 \hat{i} + 4 \hat{j} + 6 \hat{i} = 8 \hat{i} + 4 \hat{j} \] Thus, the resulting vector is \( 4 (2 \hat{i} - \hat{j}) \).
Step 2: Final Answer.
Thus, \( \mathbf{P} - \mathbf{Q} = 4 (2 \hat{i} - \hat{j}) \).
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