Step 1: Calculate wavelength of sound.
\[
\lambda = \frac{v}{f} = \frac{340}{340} = 1 \, \text{m} = 100 \, \text{cm}
\]
Step 2: Resonance condition for closed pipe.
For the first resonance in a closed pipe:
\[
L = \frac{\lambda}{4}
\]
Step 3: Length of air column at resonance.
\[
L = \frac{100}{4} = 25 \, \text{cm}
\]
Step 4: Finding height of water.
Total length of cylinder = 100 cm
\[
\text{Height of water} = 100 - 25 = 75 \, \text{cm}
\]
But minimum height of water corresponds to minimum air column length at resonance, hence
\[
\boxed{25 \, \text{cm}}
\]