Step 1: Recall the standard formula for \(\sin5\theta\).
We know that
\[
\sin5\theta
=
5\sin\theta
-20\sin^3\theta
+16\sin^5\theta
\]
We now express everything in terms of \(\cos\theta\).
Step 2: Use the identity
\[
\sin^2\theta=1-\cos^2\theta
\]
First,
\[
\sin^3\theta
=
\sin\theta(1-\cos^2\theta)
\]
and
\[
\sin^5\theta
=
\sin\theta(1-\cos^2\theta)^2
\]
Substituting into the formula,
\[
\sin5\theta
=
5\sin\theta
-20\sin\theta(1-\cos^2\theta)
+16\sin\theta(1-\cos^2\theta)^2
\]
Step 3: Expand the expression.
First expand:
\[
(1-\cos^2\theta)^2
=
1-2\cos^2\theta+\cos^4\theta
\]
Thus,
\[
\sin5\theta
=
5\sin\theta
-20\sin\theta
+20\cos^2\theta\sin\theta
\]
\[
+16\sin\theta
-32\cos^2\theta\sin\theta
+16\cos^4\theta\sin\theta
\]
Now combine like terms.
Coefficient of \(\sin\theta\):
\[
5-20+16=1
\]
Coefficient of \(\cos^2\theta\sin\theta\):
\[
20-32=-12
\]
Hence,
\[
\sin5\theta
=
16\cos^4\theta\sin\theta
-12\cos^2\theta\sin\theta
+\sin\theta
\]
Step 4: Match with the given options.
The obtained identity exactly matches option (1).
Step 5: Final conclusion.
Therefore,
\[
\boxed{
\sin5\theta
=
16\cos^4\theta\sin\theta
-12\cos^2\theta\sin\theta
+\sin\theta
}
\]
Hence, the correct option is (1).