Step 1: Concept
For an ideal transformer, the ratio of voltages is equal to the ratio of the number of turns: $\frac{V_{s}}{V_{p}} = \frac{N_{s}}{N_{p}}$.
Step 2: Meaning
If $N_{s} > N_{p}$, it is a step-up transformer that increases voltage.
Step 3: Analysis
We are given $N_{s} = 2N_{p}$, so $\frac{N_{s}}{N_{p}} = 2$. This implies $V_{s} = 2 \times V_{p}$.
Step 4: Conclusion
Given input $V_{p} = 220V$, the output $V_{s} = 220 \times 2 = 440V$.
Final Answer: (C)