Question:
A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is:
A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is:
Updated On: Apr 20, 2026
- \(\frac{Βνπr^2}{2}\) and P is at higher potential
- πrBv and R is at higher potential
- 2rBv and R is at higher potential
- Zero
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The Correct Option is C
Solution and Explanation
The correct option (C): 2rBv and R is at higher potential
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