Question:
(A) + tap water \(\rightarrow\) white turbidity soluble in aq NH\(_3\)
(A) \(\xrightarrow{\Delta}\) residue (B) + NO\(_2\) + O\(_2\)
Aqueous (A) gives brown ring on adding FeSO\(_4\) and conc. H\(_2\)SO\(_4\). Identify (A).
(A) + tap water \(\rightarrow\) white turbidity soluble in aq NH\(_3\)
(A) \(\xrightarrow{\Delta}\) residue (B) + NO\(_2\) + O\(_2\)
Aqueous (A) gives brown ring on adding FeSO\(_4\) and conc. H\(_2\)SO\(_4\). Identify (A).
(A) \(\xrightarrow{\Delta}\) residue (B) + NO\(_2\) + O\(_2\)
Aqueous (A) gives brown ring on adding FeSO\(_4\) and conc. H\(_2\)SO\(_4\). Identify (A).
Show Hint
Brown ring test is specific for nitrate ion (NO\(_3^-\)).
Updated On: Apr 23, 2026
- NaNO\(_3\)
- AgNO\(_3\)
- NaNO\(_2\)
- AgNO\(_2\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Tap water contains Cl\(^-\) ions. White turbidity soluble in NH\(_3\) indicates AgCl. Brown ring test confirms NO\(_3^-\).
Step 2: Detailed Explanation:
AgNO\(_3\) + tap water (Cl\(^-\)) \(\rightarrow\) AgCl (white turbidity). AgCl dissolves in NH\(_3\) forming [Ag(NH\(_3\))\(_2\)]\(^+\).
Heating AgNO\(_3\): 2AgNO\(_3\) \(\xrightarrow{\Delta}\) 2Ag + 2NO\(_2\) + O\(_2\).
Brown ring test: NO\(_3^-\) + 3Fe\(^{2+}\) + 4H\(^+\) \(\rightarrow\) NO + 3Fe\(^{3+}\) + 2H\(_2\)O; NO + Fe\(^{2+}\) \(\rightarrow\) [Fe(NO)]\(^{2+}\) (brown).
Step 3: Final Answer:
Thus, (A) = AgNO\(_3\).
Tap water contains Cl\(^-\) ions. White turbidity soluble in NH\(_3\) indicates AgCl. Brown ring test confirms NO\(_3^-\).
Step 2: Detailed Explanation:
AgNO\(_3\) + tap water (Cl\(^-\)) \(\rightarrow\) AgCl (white turbidity). AgCl dissolves in NH\(_3\) forming [Ag(NH\(_3\))\(_2\)]\(^+\).
Heating AgNO\(_3\): 2AgNO\(_3\) \(\xrightarrow{\Delta}\) 2Ag + 2NO\(_2\) + O\(_2\).
Brown ring test: NO\(_3^-\) + 3Fe\(^{2+}\) + 4H\(^+\) \(\rightarrow\) NO + 3Fe\(^{3+}\) + 2H\(_2\)O; NO + Fe\(^{2+}\) \(\rightarrow\) [Fe(NO)]\(^{2+}\) (brown).
Step 3: Final Answer:
Thus, (A) = AgNO\(_3\).
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