Question:
A system is provided 50 J of heat and work done on the system is 10 J. What is change in internal energy ?
A system is provided 50 J of heat and work done on the system is 10 J. What is change in internal energy ?
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Use the first law \(\Delta U = q + w\) with both terms positive here.
Updated On: Oct 1, 2026
- \(40\) J
- \(60\) J
- \(30\) J
- \(50\) J
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
First law of thermodynamics: \(\Delta U = q + w\), where \(q\) is heat absorbed by the system and \(w\) is work done on the system.
Step 2: Detailed Explanation
Heat is given to the system, so \(q = +50\) J.
Work is done on the system, so \(w = +10\) J.
\[ \Delta U = 50 + 10 = 60\ \text{J} \]
Option (A) subtracts the work, which would be right only if the system did the work, so it does not apply here.
Final Answer:
The internal energy rises by 60 J, option (B). \[ \boxed{60\ \text{J (B)}} \]
First law of thermodynamics: \(\Delta U = q + w\), where \(q\) is heat absorbed by the system and \(w\) is work done on the system.
Step 2: Detailed Explanation
Heat is given to the system, so \(q = +50\) J.
Work is done on the system, so \(w = +10\) J.
\[ \Delta U = 50 + 10 = 60\ \text{J} \]
Option (A) subtracts the work, which would be right only if the system did the work, so it does not apply here.
Final Answer:
The internal energy rises by 60 J, option (B). \[ \boxed{60\ \text{J (B)}} \]
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