Question:
A substance C\(_4\)H\(_8\)O yields on oxidation a compound, C\(_4\)H\(_8\)O\(\) which gives an oxime and a positive iodoform test. The original substance on treatment with conc. H\(_2\)SO\(_4\) gives C\(_4\)H\(_8\). The structure of the compound is
A substance C\(_4\)H\(_8\)O yields on oxidation a compound, C\(_4\)H\(_8\)O\(\) which gives an oxime and a positive iodoform test. The original substance on treatment with conc. H\(_2\)SO\(_4\) gives C\(_4\)H\(_8\). The structure of the compound is
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The positive iodoform test is a characteristic of compounds with a methyl group attached to a carbonyl group.
Updated On: Jan 12, 2026
- CH\(_3\)COCH\(_2\)OH
- CH\(_3\)COOH
- CH\(_3\)COCH\(_2\)CH\(_3\)
- CH\(_3\)CH\(_2\)OH
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The Correct Option is A
Solution and Explanation
Step 1: Analyze the oxidation and tests.
The given tests (iodoform and oxime) suggest that the original compound is acetaldehyde, which on oxidation gives acetic acid.
Step 2: Conclusion.
Thus, the compound is CH\(_3\)COCH\(_2\)OH.
Final Answer: \[ \boxed{\text{CH}_3\text{COCH}_2\text{OH}} \]
The given tests (iodoform and oxime) suggest that the original compound is acetaldehyde, which on oxidation gives acetic acid.
Step 2: Conclusion.
Thus, the compound is CH\(_3\)COCH\(_2\)OH.
Final Answer: \[ \boxed{\text{CH}_3\text{COCH}_2\text{OH}} \]
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