Question:
A sub-atomic particle of mass \(2.2 \times 10^{-2} \, kg\) is moving with a velocity of \(3.0 \times 10^5 \, ms^{-1}\). What is its de Broglie wavelength? (Planck's constant \(h = 6.6 \times 10^{-34} \, Js\))
A sub-atomic particle of mass \(2.2 \times 10^{-2} \, kg\) is moving with a velocity of \(3.0 \times 10^5 \, ms^{-1}\). What is its de Broglie wavelength? (Planck's constant \(h = 6.6 \times 10^{-34} \, Js\))
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De Broglie wavelength decreases with increasing mass and velocity.
Updated On: Apr 24, 2026
- 1 pm
- 0.1 pm
- 2 pm
- 0.2 pm
- 0.5 pm
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The Correct Option is B
Solution and Explanation
Concept:
De Broglie wavelength:
\[
\lambda = \frac{h}{mv}
\]
Step 1: Substitute values.
\[ \lambda = \frac{6.6 \times 10^{-34}}{(2.2 \times 10^{-27})(3.0 \times 10^5)} \]
Step 2: Simplify.
\[ \lambda = \frac{6.6}{6.6} \times 10^{-34+27-5} = 10^{-12} \, m \] \[ \lambda = 0.1 \, pm \]
Step 1: Substitute values.
\[ \lambda = \frac{6.6 \times 10^{-34}}{(2.2 \times 10^{-27})(3.0 \times 10^5)} \]
Step 2: Simplify.
\[ \lambda = \frac{6.6}{6.6} \times 10^{-34+27-5} = 10^{-12} \, m \] \[ \lambda = 0.1 \, pm \]
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