Question:
A string of length ℓ is fixed at both ends. It is vibrating in its 3ʳd overtone with maximum amplitude a. The amplitude at a distance ℓ/3 from one end is:
A string of length ℓ is fixed at both ends. It is vibrating in its 3ʳd overtone with maximum amplitude a. The amplitude at a distance ℓ/3 from one end is:
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For a string fixed at both ends:
n-th overtone = (n+1)th harmonic
Always write the correct wave equation.
Updated On: Mar 19, 2026
- \(a\)
- \(0\)
- \(\dfrac{\sqrt{3}a}{2}\)
- (a)/(2)
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The Correct Option is C
Solution and Explanation
Step 1: Third overtone corresponds to the fourth harmonic.
Step 2: Equation of stationary wave: y = asin((4π x)/(ℓ))
Step 3: At x=ℓ/3: y = asin((4π)/(3)) = a(√(3)/2)
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