Question:
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is
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Horizontal velocity in a projectile is always constant if air resistance is neglected.
Updated On: May 12, 2026
- $\text{E}^2 \sin^2 \theta$
- $\text{E} \sin \theta$
- $E \cos^2 \theta$
- $\text{E} \cos \theta$
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The Correct Option is C
Solution and Explanation
Step 1: Concept
At the highest point of projectile motion, the vertical component of velocity is zero ($v_y = 0$), but the horizontal component remains constant ($v_x = u \cos \theta$).
Step 2: Meaning
Initial $KE = E = \frac{1}{2} m u^2$.
Step 3: Analysis
$KE$ at highest point $= \frac{1}{2} m (u \cos \theta)^2 = (\frac{1}{2} m u^2) \cos^2 \theta$.
Step 4: Conclusion
$KE_{peak} = E \cos^2 \theta$. Final Answer: (C)
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