A square, whose side is 2 m, has its corners cut away so as to form an octagon with all sides equal. Then the length of each side of the octagon, in metres, is:
Show Hint
In regular octagon formation from square, use symmetry and corner right-triangle properties to relate side lengths.
Let each cut-off be length $x$. Each octagon side consists of original square side minus two $x$ plus diagonal of cut square ($x\sqrt{2}$). Equation:
$2 - 2x + x\sqrt{2} = s$ (side length of octagon). Geometry shows $x = 2 - 2s$. Substituting and solving gives $s = \frac{2}{\sqrt{2} + 1}$.