Question:

A square gate of size \(1\,\text{m} \times 1\,\text{m}\) is hinged at its mid-point. A fluid of density \(\rho\) fills the space to the left of the gate. The force \(F\) required to hold the gate stationary is: 

Show Hint

For fluid pressure problems: \[ p=\rho g h \] Always take moments about the hinge point.
Updated On: Mar 23, 2026
  • \(\dfrac{\rho g}{3}\)
  • \(\dfrac{\rho g}{2}\)
  • \(6\rho g\)
  • \(\dfrac{\rho g}{8}\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation


Step 1:
Pressure at depth \(y\): \[ p=\rho g y \]
Step 2:
Force on an elemental strip: \[ dF = \rho g y \cdot dy \]
Step 3:
Total torque about hinge: \[ \tau = \int_0^1 \rho g y \cdot y\,dy = \rho g \int_0^1 y^2 dy = \frac{\rho g}{3} \]
Step 4:
Balancing torque gives required force: \[ F=\frac{\rho g}{3} \]
Was this answer helpful?
0
0