A square gate of size \(1\,\text{m} \times 1\,\text{m}\) is hinged at its mid-point. A fluid of density \(\rho\) fills the space to the left of the gate. The force \(F\) required to hold the gate stationary is:
Show Hint
For fluid pressure problems:
\[
p=\rho g h
\]
Always take moments about the hinge point.
Step 1: Pressure at depth \(y\):
\[
p=\rho g y
\]
Step 2: Force on an elemental strip:
\[
dF = \rho g y \cdot dy
\]
Step 3: Total torque about hinge:
\[
\tau = \int_0^1 \rho g y \cdot y\,dy = \rho g \int_0^1 y^2 dy = \frac{\rho g}{3}
\]
Step 4: Balancing torque gives required force:
\[
F=\frac{\rho g}{3}
\]