Question:
A source of sound S emitting waves of frequency 100Hz and an observer O are located at some distance from each other. The source is moving with a speed of 19.4m s⁻1 at an angle of 60^∘ with the source–observer line as shown. The observer is at rest. The apparent frequency observed is (velocity of sound in air =330m s⁻1):
A source of sound S emitting waves of frequency 100Hz and an observer O are located at some distance from each other. The source is moving with a speed of 19.4m s⁻1 at an angle of 60^∘ with the source–observer line as shown. The observer is at rest. The apparent frequency observed is (velocity of sound in air =330m s⁻1):
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Only the component of velocity along the line of sight affects Doppler shift.
Updated On: Mar 20, 2026
- \(103\,\text{Hz}\)
- \(106\,\text{Hz}\)
- \(97\,\text{Hz}\)
- 100Hz
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The Correct Option is A
Solution and Explanation
Step 1: Component of source velocity towards observer: vₛ=19.4\cos60^∘=9.7m s⁻1
Step 2: Doppler formula: f' = f(v)/(v-vₛ) =100(330)/(330-9.7)≈103Hz
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