The correct answer is option (B): 82000 g/mol
Explanation: The osmotic pressure formula is given by:
\(\pi = \frac{nRT}{V}\)
Where:
Substitute into the formula:
\[ 3.0 \times 10^{-4} = \frac{\left(\frac{4}{M}\right)(0.08206)(300)}{4} \]
Multiply both sides by 4:
\[ 1.2 \times 10^{-3} = \frac{(4)(0.08206)(300)}{M} \]
Solve for M:
\[ M = \frac{(4)(0.08206)(300)}{1.2 \times 10^{-3}} = \frac{98.472}{1.2 \times 10^{-3}} = 82060 \approx 82000 \text{ g/mol} \]
Hence, the molar mass of the polymer is approximately 82000 g/mol.
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