A solid metal cube of edge length 2 cm is moving in a positive y-direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z-direction. The potential difference between the two faces of the cube perpendicular to the x-axis, is -
Show Hint
- 2 mV
- 12 mV
- 6 mV
- 1 mV
The Correct Option is B
Solution and Explanation
So a potential difference appears between the two faces perpendicular to x, separated by \(l = 2\) cm \(= 0.02\) m.
\(V = Bvl = 0.1\times6\times0.02 = 1.2\times10^{-2}\) V \(= 12\) mV.
Answer: (2) 12 mV
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