Question

A solenoid has core of a material with relative permeability 301 and its winding carries a current of 2 A . The number of turns of the solenoid is 600 per metre. The magnetization of the material is

• A. \(3.6\times 10^{-5}\text{ }\mathrm{A}/\mathrm{m}\)
• B. \(3.6\times 10^{5}\text{ }\mathrm{A}/\mathrm{m}\)
• C. \(1.8\times 10^{-5}\text{ }\mathrm{A}/\mathrm{m}\)
• D. \(1.8\times 10^{5}\text{ }\mathrm{A}/\mathrm{m}\)

Hint:

Magnetization is \(M=\chi_m H\) with \(\chi_m=\mu_r-1\) and \(H=nI\).

Answer 1

The Correct Option is B

Step 1: Understanding the Concept
Magnetizing field in the solenoid is \(H=nI\). Magnetization is \(M=\chi_m H\), where \(\chi_m=\mu_r-1\).

Step 2: Magnetizing field
\(H=nI=600\times2=1200\ \mathrm{A/m}\).

Step 3: Susceptibility
\(\chi_m=\mu_r-1=301-1=300\).

Step 4: Magnetization
\(M=300\times1200=3.6\times10^{5}\ \mathrm{A/m}\).

Final Answer:
The magnetization is \(3.6\times10^{5}\) A/m. \[ \boxed{\text{(B) }3.6\times 10^{5}\text{ A/m}} \]