Question:
A small block of mass \(m\) is kept on a rough inclined surface of inclination \(\theta\) fixed in an elevator. The elevator goes up with a uniform velocity \(v\) and the block does not slide on the wedge. The work done by the force of friction on the block in time \(t\) will be:
A small block of mass \(m\) is kept on a rough inclined surface of inclination \(\theta\) fixed in an elevator. The elevator goes up with a uniform velocity \(v\) and the block does not slide on the wedge. The work done by the force of friction on the block in time \(t\) will be:
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If there is no relative motion between surfaces, friction does no work.
Updated On: Mar 24, 2026
- zero
- \(mgvt\cos^2\theta\)
- \(mgvt\sin^2\theta\)
- \(mgvt\sin2\theta\)
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The Correct Option is A
Solution and Explanation
Step 1: Elevator moves with constant velocity, so acceleration is zero.
Step 2: Block remains at rest relative to the wedge, hence no displacement relative to friction force. \[ \text{Work done} = 0 \]
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