Step 1: Understanding free surface effect.
The free surface effect depends on the second moment of area (moment of inertia) of the tank's free surface. \[ I = \frac{b^3 l}{12} \] where \( b \) is the breadth of the tank (transverse dimension), and \( l \) is the length.
Step 2: Compare Tank A and Tank B.
Tank A: \( b = 16 \, {m} \), \( l = 12 \, {m} \) \[ I_A = \frac{16^3 \cdot 12}{12} = 4096 \] Tank B: \( b = 12 \, {m} \), \( l = 16 \, {m} \) \[ I_B = \frac{12^3 \cdot 16}{12} = 2304 \] Step 3: Select the tank with smaller free surface moment.
Since \( I_B<I_A \), Tank B contributes less to the free surface effect. Hence, filling 100% of the ballast water in Tank B is the best option.
A ship with a standard right-handed coordinate system has positive \(x\), \(y\), and \(z\) axes respectively pointing towards bow, starboard, and down as shown in the figure. If the ship takes a starboard turn, then the drift angle, sway velocity, and the heel angle of the ship for a steady yaw rate respectively are: 
The GZ curve for a stable ship is shown in the figure, where \( P \) is a point of inflection on the curve. Match the labels in Column 1 with the corresponding descriptions in Column 2. 
Consider a case where the load \( Q \) for a ship structure has only statistical uncertainties. The probability density function of the load \( p_Q(x) \) is shown in the figure. The characteristic limit value of the load \( Q_L \) is 1.5 and the factor of safety is 1. Which of the following probability of exceedance value(s) of the load will lead to a safe design?
