Question:

A semiconductor has an electron concentration of $8\times 10^{13} / \mathrm{m}^{3}$ and hole concentration of $5.5\times 10^{12} / \mathrm{m}^{3}$. The semiconductor is

Show Hint

In $n$-type semiconductor, electrons are majority carriers.
Updated On: Apr 8, 2026
  • $n$-type
  • $p$-type
  • intrinsic semiconductor
  • $p$-$n$ junction
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
In $n$-type semiconductors, electrons are majority carriers.
Step 2: Detailed Explanation:
Electron concentration ($n_e = 8 \times 10^{13}$) is greater than hole concentration ($n_h = 5.5 \times 10^{12}$). Hence, it is an $n$-type semiconductor.
Step 3: Final Answer:
The semiconductor is $n$-type.
Was this answer helpful?
0
0

Top MET Physics Questions

View More Questions

Top MET Semiconductor electronics: materials, devices and simple circuits Questions

View More Questions

Top MET Questions

View More Questions