Question:
A sample of ammonium phosphate (NH\(_4\))\(_3\)PO\(_4\) contains 3.18 moles of H-atom. The number of moles of O-atom in the sample is
A sample of ammonium phosphate (NH\(_4\))\(_3\)PO\(_4\) contains 3.18 moles of H-atom. The number of moles of O-atom in the sample is
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(NH\(_4\))\(_3\)PO\(_4\) contains: 3N, 12H, 1P, 4O.
Updated On: Apr 23, 2026
- 0.265
- 0.795
- 1.06
- 3.18
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
In (NH\(_4\))\(_3\)PO\(_4\): H atoms = 12 per formula, O atoms = 4 per formula.
Step 2: Detailed Explanation:
Moles of (NH\(_4\))\(_3\)PO\(_4\) = \(\frac{3.18}{12} = 0.265\) mol.
Moles of O atoms = \(0.265 \times 4 = 1.06\) mol.
Step 3: Final Answer:
Thus, moles of O-atom = 1.06.
In (NH\(_4\))\(_3\)PO\(_4\): H atoms = 12 per formula, O atoms = 4 per formula.
Step 2: Detailed Explanation:
Moles of (NH\(_4\))\(_3\)PO\(_4\) = \(\frac{3.18}{12} = 0.265\) mol.
Moles of O atoms = \(0.265 \times 4 = 1.06\) mol.
Step 3: Final Answer:
Thus, moles of O-atom = 1.06.
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