Question:

A same torque is applied to a disc and a ring of equal mass and radii then

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Lower moment of inertia results in higher angular acceleration for the same torque.
Updated On: Jun 19, 2026
  • the ring will rotate with greater angular frequency.
  • both will rotate with same angular frequency.
  • the disc will rotate with greater angular frequency.
  • both will rotate with same angular velocity.
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The Correct Option is C

Solution and Explanation

Step 1: Concept
Torque $\tau = I\alpha$, where $I$ is moment of inertia and $\alpha$ is angular acceleration.

Step 2: Analysis

- $I_{\text{ring}} = MR^2$
- $I_{\text{disc}} = \frac{1}{2}MR^2$
Since $I_{\text{ring}} > I_{\text{disc}}$, for the same torque, $\alpha_{\text{disc}} > \alpha_{\text{ring}}$.

Step 3: Calculation

Higher angular acceleration leads to a higher change in angular velocity and frequency in the same time interval.

Step 4: Conclusion

Hence, the disc will rotate with greater angular frequency. Final Answer: (C)
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