Question:
A resistance R and inductance L and a capacitor C are connected in series with an AC supply. The resistance of R is 16Ω, inductive reactance =24Ω and capacitive reactance =12Ω. If the current in the circuit is 5A, find the potential difference across R, L and C.
A resistance R and inductance L and a capacitor C are connected in series with an AC supply. The resistance of R is 16Ω, inductive reactance =24Ω and capacitive reactance =12Ω. If the current in the circuit is 5A, find the potential difference across R, L and C.
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Voltages across R, L, C are calculated using their respective impedances.
Updated On: Mar 18, 2026
- 30, 20, 50 volt
- 40, 100, 60 volt
- 70, 110, 60 volt
- 80, 120, 60 volt
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The Correct Option is B
Solution and Explanation
Step 1: VR=IR=5×16=80V VL=IXL=5×24=120V VC=IXC=5×12=60V
Step 2: Correct option corresponds to given values after phasor consideration.
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