Question:

A regular polygon has 20 sides. The number of triangles that can be drawn by using the vertices but not using the sides are

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Total triangles sharing NO sides $= \binom{n}{3} - n - n(n-4)$.
Updated On: May 14, 2026
  • $1140$
  • $800$
  • $340$
  • $20$
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The Correct Option is B

Solution and Explanation


Step 1: Concept

The total number of triangles from $n$ vertices is $\binom{n}{3}$. We must subtract triangles that use one side or two sides of the polygon.

Step 2: Meaning

For an $n$-sided polygon, the number of triangles with no sides shared is given by the formula: $\frac{n(n-4)(n-5)}{6}$.

Step 3: Analysis

Here $n = 20$. Triangles sharing no sides $= \frac{20(20-4)(20-5)}{6}$. $= \frac{20 \times 16 \times 15}{6} = \frac{4800}{6} = 800$.

Step 4: Conclusion

There are 800 such triangles. Final Answer: (B)
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