Question:

A ray parallel to the principal axis is incident at \(30^\circ\) from the normal on a concave mirror having radius of curvature \(R\). The point on the principal axis where rays are focused is \(O\) such that \(PQ\) is:



 

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For oblique incidence on spherical mirrors, focal length depends on angle: \[ f_{\theta} = \frac{R}{2}\cos\theta \] Use geometry instead of paraxial approximation.
Updated On: Mar 23, 2026
  • \(\dfrac{R}{2}\)
  • \(\dfrac{R}{\sqrt{3}}\)
  • \(\dfrac{2\sqrt{R}-R}{\sqrt{2}}\)
  • \(R\left(1-\dfrac{1}{\sqrt{3}}\right)\)
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The Correct Option is D

Solution and Explanation


Step 1:
For a ray parallel to the principal axis, reflection occurs such that angle of incidence equals angle of reflection.
Step 2:
Geometry of the concave mirror gives focal shift due to oblique incidence.
Step 3:
Using mirror geometry: \[ PQ = R\left(1-\cos 30^\circ\right) \]
Step 4:
Substitute \(\cos 30^\circ = \frac{\sqrt{3}}{2}\): \[ PQ = R\left(1-\frac{\sqrt{3}}{2}\right) = R\left(1-\frac{1}{\sqrt{3}}\right) \]
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