Question

A projectile projected at an angle 30^ from the horizontal has a range R. If the angle of projection at the same initial velocity is 60^, the range will be:

• A. R
• B. R/2
• C. 2R
• D. R²

Hint:

Angles θ and 90^-θ give the same range for a projectile.

Answer 1

The Correct Option is A

Step 1: Range of a projectile, R = (u² 2θ)/(g)
Step 2: For θ = 30^, 60^ = √(3)2
Step 3: For θ = 60^, 120^ = 60^
Step 4: Hence, the range remains the same.