Question:
A projectile is fired with a velocity \(u\) making an angle \(\theta\) with the horizontal. What is the magnitude of change in velocity when it is at the highest point?
A projectile is fired with a velocity \(u\) making an angle \(\theta\) with the horizontal. What is the magnitude of change in velocity when it is at the highest point?
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At the highest point of projectile motion, vertical velocity is zero but horizontal velocity remains unchanged.
Updated On: Mar 24, 2026
- \(u\cos\theta\)
- \(u\)
- \(u\sin\theta\)
- \(u\cos\theta - u\)
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The Correct Option is C
Solution and Explanation
Step 1: Initial velocity components: \[ u_x = u\cos\theta,\quad u_y = u\sin\theta \]
Step 2: At the highest point, vertical velocity becomes zero while horizontal remains unchanged.
Step 3: Change in velocity occurs only in vertical direction: \[ \Delta v = u\sin\theta \]
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