Question:
A power transmission line feeds input voltage 2500 V to a step down transformer with its primary winding having 3000 turns. The number of turns in the secondary in order to get output voltage of 220 V is:
A power transmission line feeds input voltage 2500 V to a step down transformer with its primary winding having 3000 turns. The number of turns in the secondary in order to get output voltage of 220 V is:
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In ideal transformers, voltage ratio equals turns ratio: \(V_s/V_p = N_s/N_p\).
Updated On: Jul 18, 2026
- 264
- 288
- 312
- 244
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The Correct Option is A
Solution and Explanation
Step 1: Transformer turns ratio relation.
For an ideal transformer: \[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \]
Step 2: Identify given values.
\[ V_p = 2500\, V,\quad V_s = 220\, V,\quad N_p = 3000 \]
Step 3: Apply formula.
\[ \frac{220}{2500} = \frac{N_s}{3000} \]
Step 4: Solve for \(N_s\).
\[ N_s = 3000 \times \frac{220}{2500} \]
Step 5: Simplify.
\[ N_s = 3000 \times 0.088 = 264 \]
Step 6: Final conclusion.
\[ \boxed{264} \]
For an ideal transformer: \[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \]
Step 2: Identify given values.
\[ V_p = 2500\, V,\quad V_s = 220\, V,\quad N_p = 3000 \]
Step 3: Apply formula.
\[ \frac{220}{2500} = \frac{N_s}{3000} \]
Step 4: Solve for \(N_s\).
\[ N_s = 3000 \times \frac{220}{2500} \]
Step 5: Simplify.
\[ N_s = 3000 \times 0.088 = 264 \]
Step 6: Final conclusion.
\[ \boxed{264} \]
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