Given :
Mass of ball = m
Initial velocity = u
Final velocity = v
Now,
\(⇒e=\frac{\text{Veloctiy of seperation}}{\text{Velocity of approach}}\)
\(⇒1=\frac{v_2-v_1}{u_2-u_1}\)
\(1=\frac{v_0-v}{u+v}\)
⇒ u + v = v0 - v
⇒ v0 = u + 2v
So, the correct option is (C) : u + 2v.
A train of weight \(10^7\ N\) is running on a level track with uniform speed of \({36\, km\, h^{-1}}\). The frictional force is 0.5 kg f per quintal. If \(g ={ 10 \, m \, s^{-2}}\), power of engine is
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