Question:
A passenger in an open car travelling at 30 m/s throws a ball out over the bonnet. Relative to the car, the initial velocity of the ball is 20 m/s at 60^ to the horizontal. The angle of projection of the ball with respect to the horizontal road will be:
A passenger in an open car travelling at 30 m/s throws a ball out over the bonnet. Relative to the car, the initial velocity of the ball is 20 m/s at 60^ to the horizontal. The angle of projection of the ball with respect to the horizontal road will be:
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Always add velocities vectorially when motion is observed from a moving frame.
Updated On: Mar 18, 2026
- tan⁻¹((2)/(3))
- tan⁻¹(√(3)4)
- tan⁻¹(4√(3))
- tan⁻¹((3)/(4))
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The Correct Option is B
Solution and Explanation
Resolve velocity of ball relative to ground by vector addition of car velocity and ball’s velocity relative to car.
Horizontal component = 30 + 20\cos60^, vertical component = 20\sin60^.
Angle of projection is obtained using tanθ = (vy)/(vₓ).
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