Question:
A particle starting from extreme position performs S.H.M. The phase difference of the particle between any two successive mean positions is
A particle starting from extreme position performs S.H.M. The phase difference of the particle between any two successive mean positions is
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A particle passes the mean position every half period.
Updated On: Nov 13, 2026
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{2}\)
- \(\pi\)
- \(2\pi\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
In SHM, the particle passes through the mean position twice in every period \(T\).
Step 2: Time gap
The time between two successive passages through the mean position is \(\dfrac{T}{2}\).
Step 3: Phase difference
Phase changes by \(2\pi\) in time \(T\), so in \(\dfrac{T}{2}\) it changes by \(\pi\).
Final Answer:
The phase difference is \(\pi\). \[ \boxed{\text{(C) }\pi} \]
In SHM, the particle passes through the mean position twice in every period \(T\).
Step 2: Time gap
The time between two successive passages through the mean position is \(\dfrac{T}{2}\).
Step 3: Phase difference
Phase changes by \(2\pi\) in time \(T\), so in \(\dfrac{T}{2}\) it changes by \(\pi\).
Final Answer:
The phase difference is \(\pi\). \[ \boxed{\text{(C) }\pi} \]
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