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a particle performing u c m of radius dfrac pi 2 t
Question:
A particle performing U.C.M. of radius \( \dfrac{\pi}{2}\,\text{m} \) makes \(x\) revolutions in time \(t\). Its tangential velocity is
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Always convert revolutions into radians while calculating angular velocity.
MHT CET - 2020
MHT CET
Updated On:
Jan 30, 2026
\( \dfrac{\pi t}{x^2} \)
\( \dfrac{\pi x^2}{t} \)
\( \dfrac{\pi x}{t^2} \)
\( \dfrac{\pi^2 x}{t} \)
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The Correct Option is
D
Solution and Explanation
Step 1: Expression for tangential velocity.
Tangential velocity in uniform circular motion is \[ v = \omega r \]
Step 2: Find angular velocity.
If the particle completes \(x\) revolutions in time \(t\), \[ \omega = \frac{2\pi x}{t} \]
Step 3: Substitute given radius.
\[ r = \frac{\pi}{2} \] \[ v = \frac{2\pi x}{t} \times \frac{\pi}{2} = \frac{\pi^2 x}{t} \]
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