A particle of charge \( q \) and mass \( m \) moves in a circular orbit of radius \( r \) with angular speed \( \omega \). The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on
Show Hint
The ratio of magnetic moment to angular momentum depends on the charge and mass of the particle.
Step 1: Magnetic Moment and Angular Momentum.
For a charged particle moving in a circular orbit, the magnetic moment \( \mu \) is given by:
\[
\mu = \frac{q v r}{2}
\]
where \( v = r \omega \). The angular momentum \( L \) is:
\[
L = m r^2 \omega
\]
Thus, the ratio of the magnetic moment to angular momentum depends on \( q \) and \( m \). Step 2: Conclusion.
The correct answer is (B), \( q \) and \( m \).