Question:
A particle (m = 1 kg) slides down a frictionless track (AOC) starting from rest at a point A (height 2 m). After reaching C, the particle continues to move freely in air as a projectile. When it reaching its highest point P (height 1 m), the kinetic energy of the particle (in )) is :
(Figure drawn is schematic and not to scale; take g = 10 ms-2) 
A particle (m = 1 kg) slides down a frictionless track (AOC) starting from rest at a point A (height 2 m). After reaching C, the particle continues to move freely in air as a projectile. When it reaching its highest point P (height 1 m), the kinetic energy of the particle (in )) is :
(Figure drawn is schematic and not to scale; take g = 10 ms-2)
(Figure drawn is schematic and not to scale; take g = 10 ms-2)
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Only gravity does work on the frictionless track and in flight, so mechanical energy is conserved: KE at P = loss in potential energy from A to P.
Updated On: Oct 31, 2026
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Correct Answer: 10
Solution and Explanation
Step 1: The track is frictionless and the projectile motion is under gravity only, so total mechanical energy is conserved from A to P.
Step 2: At A the particle is at rest at height 2 m, so \(E=mgh_A=1\times10\times2=20\) J.
Step 3: At the highest point P (height 1 m), \(E=KE_P+mgh_P=KE_P+1\times10\times1\).
Step 4: \(KE_P=20-10=10\) J. (At P the vertical velocity is zero, so this is all horizontal kinetic energy.)
Answer: 10
Step 2: At A the particle is at rest at height 2 m, so \(E=mgh_A=1\times10\times2=20\) J.
Step 3: At the highest point P (height 1 m), \(E=KE_P+mgh_P=KE_P+1\times10\times1\).
Step 4: \(KE_P=20-10=10\) J. (At P the vertical velocity is zero, so this is all horizontal kinetic energy.)
Answer: 10
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