Question:
A particle carrying a charge 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 m. The value of the magnetic field produced at the center will be:
A particle carrying a charge 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 m. The value of the magnetic field produced at the center will be:
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The magnetic field due to a moving charge is proportional to the charge, velocity, and radius.
Updated On: Jan 6, 2026
- \( 10^{-7} \mu_0 \)
- \( 10^{-17} \mu_0 \)
- \( 10^{-6} \mu_0 \)
- \( 10^{-7} \mu_0 \)
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The Correct Option is B
Solution and Explanation
Step 1: Use the formula for magnetic field.
The magnetic field at the center of a circular path is given by: \[ B = \frac{\mu_0 I}{2 \pi r} \] where \( I \) is the current, and \( r \) is the radius.
Step 2: Explanation.
Since the charge is rotating, it behaves like a current, and the magnetic field produced is calculated using this formula.
Final Answer: \[ \boxed{10^{-17} \mu_0} \]
The magnetic field at the center of a circular path is given by: \[ B = \frac{\mu_0 I}{2 \pi r} \] where \( I \) is the current, and \( r \) is the radius.
Step 2: Explanation.
Since the charge is rotating, it behaves like a current, and the magnetic field produced is calculated using this formula.
Final Answer: \[ \boxed{10^{-17} \mu_0} \]
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