Question:
A paramagnetic material has \(10^{28}\) atoms/m\(^3\). Its magnetic susceptibility at temperature 350 K is \(2.8 \times 10^{-4}\). Its susceptibility at 300 K is :
A paramagnetic material has \(10^{28}\) atoms/m\(^3\). Its magnetic susceptibility at temperature 350 K is \(2.8 \times 10^{-4}\). Its susceptibility at 300 K is :
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Use Curie law: for a paramagnetic material \(\chi \propto 1/T\).
Updated On: Nov 5, 2026
- \(3.726 \times 10^{-4}\)
- \(2.672 \times 10^{-4}\)
- \(3.672 \times 10^{-4}\)
- \(3.267 \times 10^{-4}\)
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The Correct Option is D
Solution and Explanation
Curie law: \(\chi = C/T\), so \(\chi_1 T_1 = \chi_2 T_2\).
\(\chi_{300} = \chi_{350}\times\dfrac{350}{300} = 2.8\times10^{-4}\times 1.1667\).
\(\chi_{300} = 3.267\times10^{-4}\).
Answer: (4) \(3.267 \times 10^{-4}\)
\(\chi_{300} = \chi_{350}\times\dfrac{350}{300} = 2.8\times10^{-4}\times 1.1667\).
\(\chi_{300} = 3.267\times10^{-4}\).
Answer: (4) \(3.267 \times 10^{-4}\)
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