Question:
A parallel plate capacitor with air between the plates has capacitance 9 pF. The separation between the plates becomes thrice and the space between them is filled with a medium of dielectric constant 6. The capacitance becomes 'x' pF. The value of 'x' is
A parallel plate capacitor with air between the plates has capacitance 9 pF. The separation between the plates becomes thrice and the space between them is filled with a medium of dielectric constant 6. The capacitance becomes 'x' pF. The value of 'x' is
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Use \(C=K\varepsilon_0A/d\) and compare the new and old values.
Updated On: Nov 13, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Capacitance is \(C=\dfrac{K\varepsilon_0 A}{d}\), with \(K=1\) for air.
Step 2: Changes
The separation becomes \(3d\) and \(K\) becomes 6.
Step 3: Calculation
\(x=\dfrac{6}{3}\times 9\ \text{pF}=18\ \text{pF}\).
Final Answer:
The new capacitance is 18 pF. \[ \boxed{\text{(B) }18} \]
Capacitance is \(C=\dfrac{K\varepsilon_0 A}{d}\), with \(K=1\) for air.
Step 2: Changes
The separation becomes \(3d\) and \(K\) becomes 6.
Step 3: Calculation
\(x=\dfrac{6}{3}\times 9\ \text{pF}=18\ \text{pF}\).
Final Answer:
The new capacitance is 18 pF. \[ \boxed{\text{(B) }18} \]
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