Question:
A parallel plate capacitor has capacitance \( C \). If it is equally filled the parallel layers of materials of dielectric constant \( K_1 \) and \( K_2 \), its capacity becomes \( C_T \). The ratio of \( C_T \) and \( C \) is
A parallel plate capacitor has capacitance \( C \). If it is equally filled the parallel layers of materials of dielectric constant \( K_1 \) and \( K_2 \), its capacity becomes \( C_T \). The ratio of \( C_T \) and \( C \) is
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For capacitors with multiple dielectrics, the effective dielectric constant can be calculated using the formula for series or parallel combinations.
Updated On: Jan 6, 2026
- \( K_1 + K_2 \)
- \( \frac{K_1 K_2}{K_1 + K_2} \)
- \( \frac{K_1 + K_2}{K_1 K_2} \)
- \( \frac{2K_1 K_2}{K_1 + K_2} \)
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The Correct Option is C
Solution and Explanation
For a parallel plate capacitor filled with two dielectric materials, the effective dielectric constant is given by the formula \( \frac{K_1 + K_2}{K_1 K_2} \), considering the properties of the materials.
Step 2: Conclusion.
The correct ratio is \( \frac{K_1 + K_2}{K_1 K_2} \), corresponding to option (c).
Step 2: Conclusion.
The correct ratio is \( \frac{K_1 + K_2}{K_1 K_2} \), corresponding to option (c).
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