Question:
A parallel plate capacitor filled with oil of dielectric constant 3 between the plates, has a capacitance 'C'. If the oil is completely removed, then the capacitance of the capacitor will be
A parallel plate capacitor filled with oil of dielectric constant 3 between the plates, has a capacitance 'C'. If the oil is completely removed, then the capacitance of the capacitor will be
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Capacitance with a dielectric is K times the capacitance without it.
Updated On: Nov 12, 2026
- \(\sqrt{3}\text{C}\)
- \(\frac{\text{C}}{3}\)
- \(\frac{\text{C}}{\sqrt{3}}\)
- \(3\text{C}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
For a parallel plate capacitor, \(C=\dfrac{K\varepsilon_0A}{d}\).
Step 2: With oil
With \(K=3\), \(C=\dfrac{3\varepsilon_0A}{d}\).
Step 3: Without oil
Air has \(K\approx1\), so \(C'=\dfrac{\varepsilon_0A}{d}=\dfrac{C}{3}\).
Final Answer:
The new capacitance is \(\dfrac{C}{3}\). \[ \boxed{\text{(B) }\dfrac{\text{C}}{3}} \]
For a parallel plate capacitor, \(C=\dfrac{K\varepsilon_0A}{d}\).
Step 2: With oil
With \(K=3\), \(C=\dfrac{3\varepsilon_0A}{d}\).
Step 3: Without oil
Air has \(K\approx1\), so \(C'=\dfrac{\varepsilon_0A}{d}=\dfrac{C}{3}\).
Final Answer:
The new capacitance is \(\dfrac{C}{3}\). \[ \boxed{\text{(B) }\dfrac{\text{C}}{3}} \]
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