A note produces 4 beats/s with a tuning fork of frequency \(510\,\text{Hz}\) and 6 beats/s with a fork of frequency \(512\,\text{Hz}\). The frequency of the note is
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When two beat conditions are given, choose the common frequency satisfying both.
Step 1: Use beat frequency relation.
Beat frequency is given by:
\[
|f - f_0|
\]
Step 2: Apply condition with first tuning fork.
\[
|f - 510| = 4
\Rightarrow f = 514 \text{ or } 506
\]
Step 3: Apply condition with second tuning fork.
\[
|f - 512| = 6
\Rightarrow f = 518 \text{ or } 506
\]
Step 4: Common value.
The common frequency satisfying both conditions is:
\[
f = 506\,\text{Hz}
\]
Step 5: Conclusion.
The frequency of the note is \(506\,\text{Hz}\).