Question:

A note produces 4 beats/s with a tuning fork of frequency \(510\,\text{Hz}\) and 6 beats/s with a fork of frequency \(512\,\text{Hz}\). The frequency of the note is

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When two beat conditions are given, choose the common frequency satisfying both.
Updated On: Feb 11, 2026
  • \(506\,\text{Hz}\)
  • \(514\,\text{Hz}\)
  • \(518\,\text{Hz}\)
  • \(510\,\text{Hz}\)
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The Correct Option is A

Solution and Explanation

Step 1: Use beat frequency relation.
Beat frequency is given by:
\[ |f - f_0| \]
Step 2: Apply condition with first tuning fork.
\[ |f - 510| = 4 \Rightarrow f = 514 \text{ or } 506 \]
Step 3: Apply condition with second tuning fork.
\[ |f - 512| = 6 \Rightarrow f = 518 \text{ or } 506 \]
Step 4: Common value.
The common frequency satisfying both conditions is:
\[ f = 506\,\text{Hz} \]
Step 5: Conclusion.
The frequency of the note is \(506\,\text{Hz}\).
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