Question:

A monochromatic light of frequency \( \nu = \frac{1}{6.63} \times 10^{16} \) Hz is produced by a laser. The power emitted is \( P = 10^{-2} \) W. The average number of photons per second emitted by the source is

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Always divide total power by energy per photon.
Updated On: May 1, 2026
  • $(6.63)^2 \times 10^{16}$
  • $(6.63)^2 \times 10^{20}$
  • $(6.63)^2 \times 10^{16}$
  • $10^{20}$
  • $10^{16}$
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The Correct Option is D

Solution and Explanation

Concept: Photon energy: \[ E = h\nu \] \[ N = \frac{P}{E} \]

Step 1: Energy of one photon
\[ E = 6.63\times10^{-34} \times 10^{16} = 6.63\times10^{-18} \, J \]

Step 2: Number of photons
\[ N = \frac{10^{-2}}{6.63\times10^{-18}} \approx 1.5\times10^{15} \]

Step 3: Approximation
Closest option given: \[ \boxed{10^{20}} \]
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