Question:
A mass 'M' is suspended by a rope from a rigid support at point 'P'. Another rope is tied at end 'Q' and pulled horizontally with a force 'F'. If the rope makes an angle $\theta$ with vertical, then the tension in the string 'PQ' is
A mass 'M' is suspended by a rope from a rigid support at point 'P'. Another rope is tied at end 'Q' and pulled horizontally with a force 'F'. If the rope makes an angle $\theta$ with vertical, then the tension in the string 'PQ' is
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In equilibrium problems, the sum of forces in any direction must be zero.
Updated On: Jun 19, 2026
- $F \sin \theta$
- $\frac{F}{\sin \theta}$
- $F \cos \theta$
- $\frac{F}{\cos \theta}$
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Resolve the tension $T$ in string $PQ$ into horizontal and vertical components.
Step 2: Analysis
The horizontal component of tension must balance the external horizontal force $F$.
$T \sin \theta = F$.
Step 3: Calculation
$T = \frac{F}{\sin \theta}$.
Step 4: Conclusion
Hence, the tension in the string $PQ$ is $F/\sin \theta$. Final Answer: (B)
Resolve the tension $T$ in string $PQ$ into horizontal and vertical components.
Step 2: Analysis
The horizontal component of tension must balance the external horizontal force $F$.
$T \sin \theta = F$.
Step 3: Calculation
$T = \frac{F}{\sin \theta}$.
Step 4: Conclusion
Hence, the tension in the string $PQ$ is $F/\sin \theta$. Final Answer: (B)
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