Question:

A man, homozygous dominant for widows peak (WW), marries a woman with straight hairline homozygous recessive (ww). How many of their off springs will inherit straight hair line?

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A homozygous dominant parent crossed with a homozygous recessive parent gives only heterozygous offspring.
Updated On: Nov 12, 2026
  • \(100\ \%\)
  • \(50\ \%\)
  • \(25\ \%\)
  • \(0\ \%\)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
Widows peak (W) is dominant over straight hairline (w).

Step 2: Find the gametes
The father (WW) gives only W gametes, and the mother (ww) gives only w gametes.

Step 3: Cross result
Every child is Ww, which is heterozygous, and shows widows peak because W is dominant.

Step 4: Calculation
Children with straight hairline need genotype ww, but none can be ww here, so the percentage is \(0\ \%\).

Final Answer:
None of the offspring will have a straight hairline. \[ \boxed{\text{(D) }0\ \%} \]
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