Question:

A magnetic material has a relative permeability \((\mu _{r})\) of \(6001\). If it is placed in a magnetizing field (magnetic intensity) of \(H=2000\ \text{A/m}\), The total magnetic induction \((B)\) inside the material is nearly equal to
\(\mu _{0}=4\pi \times 10^{-7}\ \text{T}\cdot \text{m/A}\)

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Use B equals mu zero times mu r times H and substitute the numbers.
Updated On: Nov 12, 2026
  • \(5\pi \ T\)
  • \(3\pi \ T\)
  • \(4.8\pi \ T\)
  • \(12\pi \ T\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
Inside a magnetic material the induction is \(B=\mu_{0}\mu_{r}H\).

Step 2: Substitute
\(B=4\pi\times10^{-7}\times6001\times2000\)

Step 3: Calculation
\(6001\times2000\approx1.2\times10^{7}\), so \(B\approx4\pi\times10^{-7}\times1.2\times10^{7}=4.8\pi\ \text{T}\).

Final Answer:
The magnetic induction is about 4.8 pi tesla. \[ \boxed{\text{(C) }4.8\pi\ \text{T}} \]
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