Question:
A liquid rises to a height of \(2.4\text{ cm}\) in a glass capillary \(P\). Another glass capillary \(Q\) having diameter \(80%\) of capillary \(P\) is immersed in the same liquid. The rise of liquid in capillary \(Q\) is
A liquid rises to a height of \(2.4\text{ cm}\) in a glass capillary \(P\). Another glass capillary \(Q\) having diameter \(80%\) of capillary \(P\) is immersed in the same liquid. The rise of liquid in capillary \(Q\) is
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Capillary rise is inversely proportional to diameter.
Updated On: Apr 26, 2026
- \(2.4\text{ cm}\)
- \(3.4\text{ cm}\)
- \(3\text{ cm}\)
- \(2.5\text{ cm}\)
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The Correct Option is C
Solution and Explanation
Concept:
Capillary rise: \[ h \propto \frac{1}{r} \propto \frac{1}{d} \] Step 1: Relate heights. \[ \frac{h_1}{h_2} = \frac{d_2}{d_1} \]
Step 2: Substitute values. \[ d_2 = 0.8 d_1 \] \[ \frac{2.4}{h_2} = \frac{0.8 d_1}{d_1} = 0.8 \] \[ h_2 = \frac{2.4}{0.8} = 3 \]
Step 3: Conclusion. \[ h_2 = 3\text{ cm} \]
Capillary rise: \[ h \propto \frac{1}{r} \propto \frac{1}{d} \] Step 1: Relate heights. \[ \frac{h_1}{h_2} = \frac{d_2}{d_1} \]
Step 2: Substitute values. \[ d_2 = 0.8 d_1 \] \[ \frac{2.4}{h_2} = \frac{0.8 d_1}{d_1} = 0.8 \] \[ h_2 = \frac{2.4}{0.8} = 3 \]
Step 3: Conclusion. \[ h_2 = 3\text{ cm} \]
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