Question:

A light whose electric field vectors are completely removed by using a good polaroid, allowed to incident on the surface of the prism at Brewster's angle. Choose the most suitable option for the phenomenon related to the prism.

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At Brewster's angle the component of E in the plane of incidence (p-polarised) is not reflected at all; it is fully transmitted.
Updated On: Nov 4, 2026
  • Reflected and refracted rays will be perpendicular to each other.
  • Wave will propagate along the surface of prism.
  • No refraction, and there will be total reflection of light.
  • No reflection, and there will be total transmission of light.
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The Correct Option is D

Solution and Explanation

At Brewster's angle \(i_B\) (\(\tan i_B = \mu\)) the reflected and refracted rays are perpendicular, and the reflection coefficient for light polarised in the plane of incidence (p-polarisation) becomes zero. Only the component perpendicular to the plane of incidence is reflected.
The polaroid is oriented to remove the perpendicular component, so the light incident on the prism is p-polarised (E-vector in the plane of incidence).
For such light at Brewster's angle there is no reflected ray: the entire intensity is transmitted (refracted) into the prism.
Hence: no reflection and total transmission of light. Option (1) is a property of Brewster's angle in general but there is no reflected ray here, so it is not the "most suitable" description.
Answer: (4) No reflection, and there will be total transmission of light.
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