Question

A light having wavelength 300 nm falls on a metal surface. The work function of metal is 2.54 eV, what is stopping potential?

• A. 23 V
• B. 2.59 V
• C. 1.59 V
• D. 1.29 V

Hint:

The stopping potential can be calculated using the photoelectric equation, which involves the energy of the photons and the work function.

Answer 1

The Correct Option is B

Step 1: Use the photoelectric equation.
The energy of the photons is given by: \[ E_{\text{photon}} = h \nu \] where \( h \) is Planck’s constant and \( \nu \) is the frequency of the light. The stopping potential \( V_0 \) is related to the kinetic energy of the emitted electrons by the equation: \[ eV_0 = h \nu - W \] where \( W \) is the work function of the metal.

Step 2: Calculate the stopping potential.
Substituting the given values, the stopping potential \( V_0 \) is calculated to be 2.59 V.
Thus, the correct answer is (2).