Question

A lift of mass \(m\) is ascending with an acceleration \(a\) (\(a<g\)). The tension in the cable of the lift is ( \(g\) = acceleration due to gravity )

• A. \( m(g-a) \)
• B. \( m(g+a) \)
• C. \( m(2g+a) \)
• D. \( m(a-g) \)

Hint:

For upward acceleration of a lift, apparent weight and cable tension increase.

Answer 1

The Correct Option is B

Step 1: Forces acting on the lift.
The forces acting are tension \(T\) upward and weight \(mg\) downward.
Step 2: Applying Newton’s second law.
Since the lift is accelerating upward with acceleration \(a\), \[ T - mg = ma. \]
Step 3: Solving for tension.
\[ T = m(g+a). \]
Step 4: Conclusion.
The tension in the cable is \( m(g+a) \).