Question

A juggler keeps on moving four balls in the air throwing the balls after intervals. When one ball leaves his hand (speed = 20m/s), the position of other balls (height in m) will be (Take g = 10m/s²):

• A. 10, 20, 10
• B. 15, 20, 15
• C. 5, 15, 20
• D. 5, 10, 20

Hint:

Use symmetry of vertical motion for juggling problems.

Answer 1

The Correct Option is D

Step 1: Positions after 1 s intervals: y = ut - (1)/(2)gt²
Step 2: t=1 ⟹ y=15, t=2 ⟹ y=20, t=3 ⟹ y=15
Step 3: Correct matching gives option (D).