Question:
A hydraulic lift has two pistons: 3 cm and 5 cm. A 1875 kg mass is lifted. Find force on small piston. \( g = 10\ \text{m/s}^2 \)
A hydraulic lift has two pistons: 3 cm and 5 cm. A 1875 kg mass is lifted. Find force on small piston. \( g = 10\ \text{m/s}^2 \)
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In hydraulic systems, pressure remains constant: \( \frac{F}{A} = \text{const} \).
Updated On: May 19, 2025
- 1250 N
- 125 N
- 6750 N
- 675 N
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The Correct Option is C
Solution and Explanation
Use Pascal’s law:
\[
\frac{F_1}{A_1} = \frac{F_2}{A_2} \Rightarrow F_1 = F_2 \cdot \frac{A_1}{A_2}
\]
\[
F_2 = 1875 \cdot 10 = 18750\ \text{N}
\Rightarrow \frac{r_1^2}{r_2^2} = \left(\frac{3}{5}\right)^2 = \frac{9}{25}
\Rightarrow F_1 = 18750 \cdot \frac{9}{25} = 6750\ \text{N}
\]
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